Area and volume SAT question

Choice C is correct. The volume of a right circular cylinder is equal to $\pi a^{2}b$, where $a$ is the radius of a base of the cylinder and $b$ is the height of the cylinder. It’s given that the cylinder shown has a radius of $r$ and a height of $h$. It follows that the volume of the cylinder shown is equal to $\pi r^{2}h$. It’s given that the second right circular cylinder has a radius of $R$ and a height of $H$. It follows that the volume of the second cylinder is equal to $\pi R^{2}H$. Choice C gives $R=7r$ and $H=8h$. Substituting $7r$ for $R$ and $8h$ for $H$ in the expression that represents the volume of the second cylinder yields $\pi {(7r)}^2(8h)$, or $\pi (49r^2)(8h)$, which is equivalent to $\pi (392r^{2}h)$, or $392(\pi r^{2}h)$. This expression is equal to $392$ times the volume of the cylinder shown, $\pi r^{2}h$. Therefore, $R=7r$ and $H=8h$ could represent the radius $R$, in terms of $r$, and the height $H$, in terms of $h$, of the second cylinder.

Choice A is incorrect. Substituting $8r$ for $R$ and $7h$ for $H$ in the expression that represents the volume of the second cylinder yields $\pi {(8r)}^2(7h)$, or $\pi (64r^2)(7h)$, which is equivalent to $\pi (448r^{2}h)$, or $448(\pi r^{2}h)$. This expression is equal to $448$, not $392$, times the volume of the cylinder shown. 

Choice B is incorrect. Substituting $8r$ for $R$ and $49h$ for $H$ in the expression that represents the volume of the second cylinder yields $\pi {(8r)}^2(49h)$, or $\pi (64r^2)(49h)$, which is equivalent to $\pi (3,136r^{2}h)$, or $3,136(\pi r^{2}h)$. This expression is equal to $3,136$, not $392$, times the volume of the cylinder shown.

Choice D is incorrect. Substituting $49r$ for $R$ and $8h$ for $H$ in the expression that represents the volume of the second cylinder yields $\pi {(49r)}^2(8h)$, or $\pi (2,401r^2)(8h)$, which is equivalent to $\pi (19,208r^{2}h)$, or $19,208(\pi r^{2}h)$. This expression is equal to $19,208$, not $392$, times the volume of the cylinder shown.