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One-variable data: Distributions and measures of center and spread SAT question
Math · Problem-Solving and Data Analysis · Medium · Answer it here, explanation included.
| Country | 2012 | 2013 |
|---|---|---|
| France | 83.0 | 84.7 |
| United States | 66.7 | 69.8 |
| Spain | 57.5 | 60.7 |
| China | 57.7 | 55.7 |
| Italy | 46.4 | 47.7 |
| Turkey | 35.7 | 37.8 |
| Germany | 30.4 | 31.5 |
| United Kingdom | 26.3 | 32.2 |
| Russia | 24.7 | 28.4 |
The table above shows the number of international tourist arrivals, rounded to the nearest tenth of a million, to the top nine tourist destinations in both 2012 and 2013. Based on the information given in the table, how much greater, in millions, was the median number of international tourist arrivals to the top nine tourist destinations in 2013 than the median number in 2012, to the nearest tenth of a million?
Enter a number or fraction (like 3/17 or 0.176). Press Enter to check.
ExplanationShow
The correct answer is 1.3. The median number of tourists is found by ordering the number of tourists from least to greatest and determining the middle value from this list. When the number of tourists in 2012 is ordered from least to greatest, the middle value, or the fifth number, is 46.4 million. When the number of tourists in 2013 is ordered from least to greatest, the middle value, or the fifth number, is 47.7 million. The difference between these two medians is 
. Note that 1.3 and 13/10 are examples of ways to enter a correct answer.
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