Linear equations in one variable SAT question

Choice B is correct. Multiplying both sides of the given equation by $(3)(13)$, or $39$, yields $(39)(\frac{x+6}{3})=(39)(\frac{x+6}{13})$, or $13(x+6)=3(x+6)$. Subtracting $3(x+6)$ from both sides of this equation yields $10(x+6)=0$. Dividing both sides of this equation by $10$ yields $x+6=0$. Therefore, if $\frac{x+6}{3}=\frac{x+6}{13}$, then the value of $x+6$ is $0$. It follows that of the given choices, the value of $x+6$ is between $-2$ and $2$.

Choice A is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from conceptual or calculation errors.