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Ratios, rates, proportional relationships, and units SAT question
Math · Problem-Solving and Data Analysis · Medium · Answer it here, explanation included.
The equation above can be used to calculate the distance d, in miles, traveled by a car moving at a speed of 55 miles per hour over a period of t hours. For any positive constant k, the distance the car would have traveled after 
hours is how many times the distance the car would have traveled after 
hours?
ExplanationShow
Choice A is correct. Since the distance is equal to the amount of time multiplied by a constant, the given equation represents a proportional relationship between distance and time in this situation. Since 
, the time when 
hours is 3 times the time when 
hours. Therefore, the distance traveled after hours is 3 times the distance after hours.
Choices B and D are incorrect and may result from interpreting the proportional relationship between time and distance as additive rather than multiplicative. Choice C is incorrect and may result from an arithmetic error.
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