Percentages SAT question

The correct answer is $47.25$. It’s given that the number $w$ is $110\%$ greater than the number $z$. It follows that $w=(1+\frac{110}{100})z$, or $w=2.1z$. It’s also given that the number $z$ is $55\%$ less than $50$. It follows that $z=(1-\frac{55}{100})(50)$, or $z=0.45(50)$, which yields $z=22.5$. Substituting $22.5$ for $z$ in the equation $w=2.1z$ yields $w=2.1(22.5)$, which is equivalent to $w=47.25$. Therefore, the value of $w$ is $47.25$. Note that 47.25 and 189/4 are examples of ways to enter a correct answer.