Percentages SAT question

The correct answer is $.88$. It’s given that the number $a$ is $60\%$ greater than the positive number $b$. Therefore, $a=(1+\frac{60}{100})b$, which is equivalent to $a=(1+0.60)b$, or $a=1.60b$. It’s also given that the number $c$ is $45\%$ less than $a$. Therefore, $c=(1-\frac{45}{100})a$, which is equivalent to $c=(1-0.45)a$, or $c=0.55a$. Since $a=1.60b$, substituting $1.60b$ for $a$ in the equation $c=0.55a$ yields $c=0.55(1.60b)$, or $c=0.88b$. Thus, the number $c$ is $0.88$ times the number $b$. Note that .88 and 22/25 are examples of ways to enter a correct answer.