Percentages SAT question

Choice A is correct. It’s given that the value of the comic book increased by $167\%$ from the end of $2011$ to the end of $2012$. Therefore, if the value of the comic book at the end of $2011$ was $x$ dollars, then the value, in dollars, of the comic book at the end of $2012$ was $x+(\frac{167}{100})x$, which can be rewritten as $1x+1.67x$, or $2.67x$. It’s also given that the value of the comic book decreased by $16\%$ from the end of $2012$ to the end of $2013$. Therefore, the value, in dollars, of the comic book at the end of $2013$ was $2.67x-2.67x(\frac{16}{100})$, which can be rewritten as $2.67x-(2.67x)(0.16)$, or $2.2428x$. Thus, if the value of the comic book at the end of $2011$ was $x$ dollars, and the value of the comic book at the end of $2013$ was $2.2428x$ dollars, then from the end of $2011$ to the end of $2013$, the value of the comic book increased by $2.2428x-1x$, or $1.2428x$, dollars. Therefore, the increase in the value of the comic book from the end of $2011$ to the end of $2013$ is equal to $1.2428$ times the value of the comic book at the end of $2011$. It follows that from the end of $2011$ to the end of $2013$, the net percentage increase in the value of the comic book was $(1.2428)(100)\%$, or $124.28\%$.

Choice B is incorrect and may result from conceptual or calculation errors. 

Choice C is incorrect. This is the difference between the net percentage increase in the value of the comic book from the end of $2011$ to the end of $2012$ and the net percentage decrease in the value of the comic book from the end of $2012$ to the end of $2013$, not the net percentage increase in the value of the comic book from the end of $2011$ to the end of $2013$.

Choice D is incorrect. This is the net percentage increase in the value of the comic book from the end of $2011$ to the end of $2013$, if the value of the comic book increased by $167\%$ from the end of $2011$ to the end of $2012$ and then increased, not decreased, by $16\%$ from the end of $2012$ to the end of $2013$.